Led and power supply question
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Led and power supply question
Help required.
i purchased some damaged led torches from my work, the lights work cases were broken
so there are 24 5mm leds in the unit powered by 3 x AA 1.5v batteries, with 1 x 1.2Ohm resistor Brown/Red/Gold/Gold
i want to remove the leds in it and put in coloured ones i secured a batch of 100 coloured led's that the info says they run at 2-2.2v can i use these ones in place of the originals, ie just cut the old ones out and resolder in the new ones with leads?
i purchased some damaged led torches from my work, the lights work cases were broken
so there are 24 5mm leds in the unit powered by 3 x AA 1.5v batteries, with 1 x 1.2Ohm resistor Brown/Red/Gold/Gold
i want to remove the leds in it and put in coloured ones i secured a batch of 100 coloured led's that the info says they run at 2-2.2v can i use these ones in place of the originals, ie just cut the old ones out and resolder in the new ones with leads?
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Can you tell me why I would need to change the resistor as well? Just like to know these thingsUSS Atlantis wrote:You'll need to replace the resistor as well - up that to a 120ohm
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How would I go about converting it into a 9v system? Just change the battery pack and the resistor?
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Based on the voltage supplied and the resistor in there, it's running 3.5v LED's - I'm thinking they're WhiteMatty1973 wrote:Can you tell me why I would need to change the resistor as well? Just like to know these thingsUSS Atlantis wrote:You'll need to replace the resistor as well - up that to a 120ohm
Lower voltage LEDs need a higher value resistor to prevent overloading the LEDs - overloading can result in brighter LEDs; for as long as they last - which could be anywhere from normal lifespan (100,0000 hours) to an immediate blowout (no light at all.... ever)
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Yep - and that resistor needs to be even higher in value than just changing the LEDs to lower voltage onesMatty1973 wrote:How would I go about converting it into a 9v system? Just change the battery pack and the resistor?
Calculations say that 2.2v LED's running off a 9v power source needs a 330 ohm resistor
Ok so lets clarify this
this is the current chip that i want to use, yes it had 24 5mm white bulbs on it
http://i1103.photobucket.com/albums/g48 ... /photo.jpg
i removed the bulbs and want to replace with 3mm various colour bulbs (Predominatley white though) with leads attached, i am also going to boost it up to a 9v system.
These are the voltages of the 3mm bulbs
red bulbs: 1.9 - 2.1V, 600 - 800MCD
blue bulbs: 3.2 - 3.4V, 1500 - 2000MCD
green bulbs: 3.2 - 3.4V, 6000 - 8000MCD
yellow bulbs: 1.9 - 2.1V, 800 - 1000MCD
white bulbs: 3.2 - 3.4V, 3000 - 4000MCD
What else will i need to do, what size resistor do you think, i do have some 470ohm ones already
this is the current chip that i want to use, yes it had 24 5mm white bulbs on it
http://i1103.photobucket.com/albums/g48 ... /photo.jpg
i removed the bulbs and want to replace with 3mm various colour bulbs (Predominatley white though) with leads attached, i am also going to boost it up to a 9v system.
These are the voltages of the 3mm bulbs
red bulbs: 1.9 - 2.1V, 600 - 800MCD
blue bulbs: 3.2 - 3.4V, 1500 - 2000MCD
green bulbs: 3.2 - 3.4V, 6000 - 8000MCD
yellow bulbs: 1.9 - 2.1V, 800 - 1000MCD
white bulbs: 3.2 - 3.4V, 3000 - 4000MCD
What else will i need to do, what size resistor do you think, i do have some 470ohm ones already
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When mixing LEDs like that, the norm is to separate then into different runs
With that board, you can't do that, so the next best thing is to use a resistor based on the LOWEST value LED - which is your Reds and Yellows
Now one problem is that to accurately calculate the needed resistor value, you need two ratings - the voltage (v) and the current draw (ma)
The math for the resistor value is
R = (Vs - Vl) / I
Vs is your source voltage - 9 in this case
Vl is the load voltage - 1.9 (reds & yellows) for this circuit
I is the current draw - I'm going to use 25ma as that's a fairly typical value for LEDs - 25ma is .025A
so -> (9-1.9)/.025 = 284
So your lowest value LED needs a 284 Ohm resistor - since that's not a standard value in the E12 or E24 groupings (classes of resistors) we pop to the next HIGHER standard value
So you'll need a 300 or 330 Ohm resistor to protect the lowest value LEDs - and it should be rated at 1/2 watt one as well
What effect does this have on the others?
They'll be dimmer - reduce the power flow to a LED and the LED dims down; you have to decide if having all the LEDs on the same board is worth losing some output from all the Blues, Greens and Whites
With that board, you can't do that, so the next best thing is to use a resistor based on the LOWEST value LED - which is your Reds and Yellows
Now one problem is that to accurately calculate the needed resistor value, you need two ratings - the voltage (v) and the current draw (ma)
The math for the resistor value is
R = (Vs - Vl) / I
Vs is your source voltage - 9 in this case
Vl is the load voltage - 1.9 (reds & yellows) for this circuit
I is the current draw - I'm going to use 25ma as that's a fairly typical value for LEDs - 25ma is .025A
so -> (9-1.9)/.025 = 284
So your lowest value LED needs a 284 Ohm resistor - since that's not a standard value in the E12 or E24 groupings (classes of resistors) we pop to the next HIGHER standard value
So you'll need a 300 or 330 Ohm resistor to protect the lowest value LEDs - and it should be rated at 1/2 watt one as well
What effect does this have on the others?
They'll be dimmer - reduce the power flow to a LED and the LED dims down; you have to decide if having all the LEDs on the same board is worth losing some output from all the Blues, Greens and Whites
Thanks Ken that's great info, I don't mind the power drop as there will be plenty in the mix to still light from the inside
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