I'm going to attempt to light my PL 1/350 Refit E, and will be using a 12V DC supply with a mixture of 1.8 and 2.8 volt 3mm LEDs, all rated 20mA, broken down as follows:
12 x 1.8V (6 LED x 2 series lines, and 68 Ohm R in each line)
20 x 2.8V (4 LED x 5 series lines and 47 Ohm R per line).
I'm not planning to blink any of the lights (I'm not that clever!).
My question is:
Can I just create the 2 arrays, one for the 2Vs (and one for the 3Vs, and connect them in parallel to each other as shown above, or would I need to adjust the arrays?
Help!
Moderators: Sparky, Moderators
Have you used the LED array wizard? You can play with your array parameters until you get one that is simple to build.
Frank
Frank
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Each of the two arrays I've listed above was created using the array wizard, and I'm satisfied that they will work fine on their own. It's when I put them together that I'm worried about. When operated independantly the 2.8V array draws 100mA, with the 1.8V array drawing 40mA.macfrank wrote:Have you used the LED array wizard? You can play with your array parameters until you get one that is simple to build.
Frank
Will this change if I run both arrays in parallel? I don't think it will, since I think it will just draw a total of 140mA from the power supply (draining a 12v battery pack a little faster or giving me a higher electricity bill if I use a DC mains adapter!)
However, I'm the first to admit my inexperience here, so I was looking for someone to confirm or correct my thought processes.
There's a 'gotcha' in play here. Is your 12 volt power supply really putting out 12 volts? AC adapters that are not the 'regulated' variety generally have an output at 25% higher than the rated voltage open circuit, decreasing to the rated voltage when fully loaded. Best to make sure that you don't overdrive your leds under ANY circumstances.
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Thanks for the advice. I didn't know that. However, I've got a variable voltage adaptor. so I'll probably set it to 9V, which should keep me under the 12V even taking into account the 25%.
Failing that, I might just use a 9v battery and change the design of the arrays to reflect the reduced voltage.
Failing that, I might just use a 9v battery and change the design of the arrays to reflect the reduced voltage.