I have a usefull book on this sort of thing but the author always uses a diode.
I can understand why (with my simpleton electonics knowledge) to ensure you protect your components.
But it seems to add unecessary complications with calcultion of resistors and the like. The Diode I have bought does not actually give you stuff like forward voltages etc etc.. I know that is my issue for not chasing this down, so some of the excellent online calculators are not much good to me.
So to explain.. I am putting in 3 x 5mm White LED in parallel (I hope)

Power supply is 6V (4 x AA batteries) I have calculated that the resistor value should be 27.7 ohms..
Using R=(6v-3.5v)/0.09A
Now putting a meter over this gives me something like 5.6 Volts... that is waaaaay too much for the LED. Now this is with the DIODE in the circuit.
My confusion is based on are my calculations right with a Diode in the circuit or am I a total klutz with my calculations in the first place.
Brian T.. the electronics first time dabbler.
